Overview
I'm working on a calculus discussion question and need an explanation and answer to help me learn.
1. A customer has asked for a arch shaped like a hyperbola that is 6 feet tall, has a base that is 4 feet across, and at the narrowest width it is 3 feet across occurring at 3.5 feet from the base. What equation will meet these specifications?
2.Imagine a radio telescope with a parabolic surface.The diameter of the telescope is 310 meters and depth of the radio telescope is 172 meters deep.Using hyperbola, how many meters from the vertex should the receiver be placed?