A ball is thrown straight up from the ground with an initial velocity of 20 m/s 20 m/s.

Overview

A ball is thrown straight up from the ground with an initial velocity of

20 m/s20 \ \text{m/s}20 m/s. Its height after ttt seconds is given by:

h(t)=20t−4.9t2h(t) = 20t - 4.9t^2h(t)=20t−4.9t2

1. Find the maximum height the ball reaches.
2. Determine when it hits the ground.