Overview
Charles' Law
V1/T1=V2/T2
Hint:
K = 273 + C
or
K=273+F−321.8
using F = 32+ 1.8xC
1 L = 1000 mL
Question:
A sample of Ar gas at a temperature of 95 F occupies a volume of 455 mL. Assuming constant pressure, determine the temperature if the volume expands to 1950 mL. Show your work.
Use your own work and show all work. Use a minimum of 2 scholarly sources. Cited.
Reply to this discussion question:
Hello Class,
Here is my Option #2
1.25 A sample of H2 gas at a temperature of 269 K occupies a volume of 11 L. Assuming constant pressure, determine the new temperature if volume decreases to 10 L. Show your work.
This is the formula used for problems related to Charles's law.
𝑉1 = first volume
𝑇1= first temperature
𝑉2 = second volume
𝑇2= second temperature
Identify the known
V1=11
T1=269
V2=10
Plug in the values
11L/269K = 10/T2
Multiply all terms by the same value to eliminate fraction denominators.
T2 ⋅ .040892193309 L/K=T2⋅
Cancel multiplied terms that are in the denominator
T2⋅0.040892193309 L/K=10
Re-order terms so constants are on the left
0.040892193309 L/K⋅T2=10 L
Divide both sides by the same factor
(0.040892193309 KL*T2)/(0.040892193309 KL)=10L/(0.040892193309 KL)
Simplify
T2=244.5454545454545455 K