OnlineNursingOwl
← All nursing posts

Physics · Studypool

Biomechanics

Overview

Do i have the correct angle ?

I am currently in the process of determining my Fpx strength. However, I noticed that when I do a calculation of the form 85-90 it gives a result of -5, which affects my overall answer by giving a negative number. I think I didn't correctly determine the angle of my muscle strength. Would it be possible for this angle to be 0°? So, by doing the 85-0 calculation, we would get a positive number. Could someone help me clarify this? This is the only part where I'm stuck. I have attached my DCL. (elbow extension)

Σ𝐹⃗ = 0

X=

Σ𝐹𝑥 = 0

−𝐹𝑃𝑥 + 𝐹𝑀 sin (𝛽 − 90°) + 𝐹𝑒𝑙 sin (180 − 𝛽 − 𝜃) = 0 𝐹𝑃𝑥 =

𝐹𝑀 sin ( 𝛽 − 90°) +𝐹𝑒𝑙 sin(180 − 𝛽 − 𝜃)

𝐹𝑃𝑥 = 93.6650N sin (85 − 90) + 28.11N sin(180 − 85 − 79)

Fpx= -8.16344N +7.74816N

𝐹𝑃𝑥 = -0.4154 N←

FM= muscular force

F𝑃𝑥 and Fpy: force in the joint

Fg forearm and hand: weight of the forearm

𝐹⃗ 𝑒𝑙: force of the elastic band

[Image unavailable: Image]